1311335040 has 128 divisors (see below), whose sum is σ = 4193521920. Its totient is φ = 348549120.

The previous prime is 1311335033. The next prime is 1311335057. The reversal of 1311335040 is 405331131.

It is a tau number, because it is divible by the number of its divisors (128).

It is a junction number, because it is equal to n+sod(n) for n = 1311334998 and 1311335016.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 703710 + ... + 705570.

It is an arithmetic number, because the mean of its divisors is an integer number (32761890).

Almost surely, 2^1311335040 is an apocalyptic number.

1311335040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1311335040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2096760960).

1311335040 is an abundant number, since it is smaller than the sum of its proper divisors (2882186880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311335040 is a wasteful number, since it uses less digits than its factorization.

1311335040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2250 (or 2238 counting only the distinct ones).

The product of its (nonzero) digits is 540, while the sum is 21.

The square root of 1311335040 is about 36212.3603207524. The cubic root of 1311335040 is about 1094.5557548232. Note that the first 3 decimals are identical.

Adding to 1311335040 its reverse (405331131), we get a palindrome (1716666171).

The spelling of 1311335040 in words is "one billion, three hundred eleven million, three hundred thirty-five thousand, forty".