Base | Representation |
---|---|
bin | 11101110100010110101011… |
… | …010110010110110101011000 |
3 | 122012022222010112002002012220 |
4 | 131310112223112112311120 |
5 | 114142103443432312100 |
6 | 1142525221135304040 |
7 | 36423426663035151 |
oct | 3564265326266530 |
9 | 565288115062186 |
10 | 131141111213400 |
11 | 388706a6490342 |
12 | 1286003897b020 |
13 | 58237276bb622 |
14 | 2455399650928 |
15 | 102643437eaa0 |
hex | 7745ab596d58 |
131141111213400 has 48 divisors (see below), whose sum is σ = 406537444763400. Its totient is φ = 34970962990080.
The previous prime is 131141111213383. The next prime is 131141111213473. The reversal of 131141111213400 is 4312111141131.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 109284258745 + ... + 109284259944.
Almost surely, 2131141111213400 is an apocalyptic number.
131141111213400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131141111213400 is an abundant number, since it is smaller than the sum of its proper divisors (275396333550000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131141111213400 is a wasteful number, since it uses less digits than its factorization.
131141111213400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 218568518708 (or 218568518699 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 24.
Adding to 131141111213400 its reverse (4312111141131), we get a palindrome (135453222354531).
The spelling of 131141111213400 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred eleven million, two hundred thirteen thousand, four hundred".
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