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1311423324151 = 13762171539719
BaseRepresentation
bin10011000101010110111…
…010111101111111110111
311122101000100100110000211
4103011112322331333313
5132441243332333101
62442243133050251
7163514202221413
oct23052672757767
94571010313024
101311423324151
11466198306756
121921b5026987
139688893b845
144768a771d43
15241a6c33c51
hex13156ebdff7

1311423324151 has 8 divisors (see below), whose sum is σ = 1321209096480. Its totient is φ = 1301640643968.

The previous prime is 1311423324137. The next prime is 1311423324209. The reversal of 1311423324151 is 1514233241131.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1311423324151 - 25 = 1311423324119 is a prime.

It is a super-2 number, since 2×13114233241512 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311423324751) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 81870 + ... + 1621588.

It is an arithmetic number, because the mean of its divisors is an integer number (165151137060).

Almost surely, 21311423324151 is an apocalyptic number.

1311423324151 is a deficient number, since it is larger than the sum of its proper divisors (9785772329).

1311423324151 is a wasteful number, since it uses less digits than its factorization.

1311423324151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1546073.

The product of its digits is 8640, while the sum is 31.

Adding to 1311423324151 its reverse (1514233241131), we get a palindrome (2825656565282).

The spelling of 1311423324151 in words is "one trillion, three hundred eleven billion, four hundred twenty-three million, three hundred twenty-four thousand, one hundred fifty-one".

Divisors: 1 137 6217 851729 1539719 210941503 9572433023 1311423324151