131143112120 has 64 divisors (see below), whose sum is σ = 318518568000. Its totient is φ = 48446261248.

The previous prime is 131143112117. The next prime is 131143112171. The reversal of 131143112120 is 21211341131.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 131143112092 and 131143112101.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2431025 + ... + 2484384.

It is an arithmetic number, because the mean of its divisors is an integer number (4976852625).

Almost surely, 2^131143112120 is an apocalyptic number.

131143112120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131143112120 is an abundant number, since it is smaller than the sum of its proper divisors (187375455880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131143112120 is a wasteful number, since it uses less digits than its factorization.

131143112120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4915472 (or 4915468 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 131143112120 its reverse (21211341131), we get a palindrome (152354453251).

The spelling of 131143112120 in words is "one hundred thirty-one billion, one hundred forty-three million, one hundred twelve thousand, one hundred twenty".