Base | Representation |
---|---|
bin | 11101110101011000111001… |
… | …011010011110010100011000 |
3 | 122012120202122210202200210002 |
4 | 131311120321122132110120 |
5 | 114144240103304242130 |
6 | 1143022020425512132 |
7 | 36431524661633654 |
oct | 3565307132362430 |
9 | 565522583680702 |
10 | 131212214134040 |
11 | 38898873201a76 |
12 | 12871981042648 |
13 | 582a34949a130 |
14 | 24589c2925a64 |
15 | 10281e6701b45 |
hex | 77563969e518 |
131212214134040 has 128 divisors (see below), whose sum is σ = 328228908134400. Its totient is φ = 46879678748160.
The previous prime is 131212214134031. The next prime is 131212214134081. The reversal of 131212214134040 is 40431412212131.
It is a junction number, because it is equal to n+sod(n) for n = 131212214133994 and 131212214134012.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 149850221 + ... + 150723299.
It is an arithmetic number, because the mean of its divisors is an integer number (2564288344800).
Almost surely, 2131212214134040 is an apocalyptic number.
131212214134040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131212214134040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (164114454067200).
131212214134040 is an abundant number, since it is smaller than the sum of its proper divisors (197016694000360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131212214134040 is a wasteful number, since it uses less digits than its factorization.
131212214134040 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 882457 (or 882453 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 131212214134040 its reverse (40431412212131), we get a palindrome (171643626346171).
The spelling of 131212214134040 in words is "one hundred thirty-one trillion, two hundred twelve billion, two hundred fourteen million, one hundred thirty-four thousand, forty".
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