Base | Representation |
---|---|
bin | 1011111011110000101100… |
… | …0101010011110000110000 |
3 | 1201110101101201121101021110 |
4 | 2332330023011103300300 |
5 | 3204434421110432240 |
6 | 43523502544553320 |
7 | 2522661214344543 |
oct | 276741305236060 |
9 | 51411351541243 |
10 | 13121311030320 |
11 | 41a9798006349 |
12 | 157abb8622840 |
13 | 74244667026c |
14 | 33510952085a |
15 | 17b4ae7aac80 |
hex | bef0b153c30 |
13121311030320 has 40 divisors (see below), whose sum is σ = 40676064194736. Its totient is φ = 3499016274688.
The previous prime is 13121311030319. The next prime is 13121311030357. The reversal of 13121311030320 is 2303011312131.
It is a happy number.
13121311030320 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a tau number, because it is divible by the number of its divisors (40).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27336064407 + ... + 27336064886.
Almost surely, 213121311030320 is an apocalyptic number.
13121311030320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13121311030320 is an abundant number, since it is smaller than the sum of its proper divisors (27554753164416).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13121311030320 is a wasteful number, since it uses less digits than its factorization.
13121311030320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54672129309 (or 54672129303 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 13121311030320 its reverse (2303011312131), we get a palindrome (15424322342451).
The spelling of 13121311030320 in words is "thirteen trillion, one hundred twenty-one billion, three hundred eleven million, thirty thousand, three hundred twenty".
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