131214041112132 has 144 divisors (see below), whose sum is σ = 386836516789632. Its totient is φ = 37059570109440.

The previous prime is 131214041112113. The next prime is 131214041112157. The reversal of 131214041112132 is 231211140412131.

131214041112132 is a `hidden beast` number, since 1 + 3 + 1 + 214 + 0 + 411 + 1 + 2 + 1 + 32 = 666.

It is a super-3 number, since 3×131214041112132³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131214041112096 and 131214041112105.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 93923563 + ... + 95310354.

It is an arithmetic number, because the mean of its divisors is an integer number (2686364699928).

Almost surely, 2^{131214041112132} is an apocalyptic number.

131214041112132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

131214041112132 is an abundant number, since it is smaller than the sum of its proper divisors (255622475677500).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131214041112132 is a wasteful number, since it uses less digits than its factorization.

131214041112132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 189234058 (or 189234053 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 27.

Adding to 131214041112132 its reverse (231211140412131), we get a palindrome (362425181524263).

The spelling of 131214041112132 in words is "one hundred thirty-one trillion, two hundred fourteen billion, forty-one million, one hundred twelve thousand, one hundred thirty-two".