131231333143440 has 120 divisors (see below), whose sum is σ = 440732198387520. Its totient is φ = 34993939260672.

The previous prime is 131231333143403. The next prime is 131231333143501. The reversal of 131231333143440 is 44341333132131.

131231333143440 is a `hidden beast` number, since 1 + 3 + 1 + 2 + 313 + 331 + 4 + 3 + 4 + 4 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (120).

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a junction number, because it is equal to n+sod(n) for n = 131231333143395 and 131231333143404.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 20598331 + ... + 26205989.

It is an arithmetic number, because the mean of its divisors is an integer number (3672768319896).

Almost surely, 2^{131231333143440} is an apocalyptic number.

131231333143440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131231333143440 is an abundant number, since it is smaller than the sum of its proper divisors (309500865244080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131231333143440 is a wasteful number, since it uses less digits than its factorization.

131231333143440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5640181 (or 5640172 counting only the distinct ones).

The product of its (nonzero) digits is 93312, while the sum is 36.

Adding to 131231333143440 its reverse (44341333132131), we get a palindrome (175572666275571).

The spelling of 131231333143440 in words is "one hundred thirty-one trillion, two hundred thirty-one billion, three hundred thirty-three million, one hundred forty-three thousand, four hundred forty".