Base | Representation |
---|---|
bin | 1011111011111011100001… |
… | …1111110000111101000000 |
3 | 1201110122220111010220002221 |
4 | 2332332320133300331000 |
5 | 3210011400412032000 |
6 | 43525103355220424 |
7 | 2523123262651060 |
oct | 276767037607500 |
9 | 51418814126087 |
10 | 13124220424000 |
11 | 41aaa50310934 |
12 | 157b68aa47714 |
13 | 7427bb34c89a |
14 | 335303a9d3a0 |
15 | 17b5cee0361a |
hex | befb87f0f40 |
13124220424000 has 112 divisors (see below), whose sum is σ = 37145293735680. Its totient is φ = 4499732697600.
The previous prime is 13124220423997. The next prime is 13124220424019. The reversal of 13124220424000 is 42402242131.
It is a tau number, because it is divible by the number of its divisors (112).
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 117124540 + ... + 117236539.
Almost surely, 213124220424000 is an apocalyptic number.
13124220424000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13124220424000 is an abundant number, since it is smaller than the sum of its proper divisors (24021073311680).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13124220424000 is an equidigital number, since it uses as much as digits as its factorization.
13124220424000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 234361113 (or 234361093 counting only the distinct ones).
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 13124220424000 its reverse (42402242131), we get a palindrome (13166622666131).
The spelling of 13124220424000 in words is "thirteen trillion, one hundred twenty-four billion, two hundred twenty million, four hundred twenty-four thousand".
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