Base | Representation |
---|---|
bin | 1011111100111011010011… |
… | …1110001001101110010100 |
3 | 1201112022002122210220002121 |
4 | 2333032310332021232110 |
5 | 3210301431313300400 |
6 | 43541014311545324 |
7 | 2524300453506322 |
oct | 277166476115624 |
9 | 51468078726077 |
10 | 13141341150100 |
11 | 4207236537849 |
12 | 1582a6868b244 |
13 | 7442b9362547 |
14 | 336089806d12 |
15 | 17bc82ec621a |
hex | bf3b4f89b94 |
13141341150100 has 72 divisors (see below), whose sum is σ = 29808866485440. Its totient is φ = 5019154356480.
The previous prime is 13141341150079. The next prime is 13141341150143. The reversal of 13141341150100 is 105114314131.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3712062 + ... + 6329461.
It is an arithmetic number, because the mean of its divisors is an integer number (414012034520).
Almost surely, 213141341150100 is an apocalyptic number.
13141341150100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13141341150100 is an abundant number, since it is smaller than the sum of its proper divisors (16667525335340).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13141341150100 is a wasteful number, since it uses less digits than its factorization.
13141341150100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10042129 (or 10042122 counting only the distinct ones).
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 13141341150100 its reverse (105114314131), we get a palindrome (13246455464231).
The spelling of 13141341150100 in words is "thirteen trillion, one hundred forty-one billion, three hundred forty-one million, one hundred fifty thousand, one hundred".
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