Base | Representation |
---|---|
bin | 1011111100111011010100… |
… | …0111001101000100100001 |
3 | 1201112022002211021110020200 |
4 | 2333032311013031010201 |
5 | 3210301432420214410 |
6 | 43541014434455413 |
7 | 2524300512621600 |
oct | 277166507150441 |
9 | 51468084243220 |
10 | 13141343523105 |
11 | 4207237908706 |
12 | 1582a69434569 |
13 | 7442b99b36a5 |
14 | 336089c63a37 |
15 | 17bc832e43c0 |
hex | bf3b51cd121 |
13141343523105 has 72 divisors (see below), whose sum is σ = 26563985039592. Its totient is φ = 5992338756096.
The previous prime is 13141343523083. The next prime is 13141343523193. The reversal of 13141343523105 is 50132534314131.
13141343523105 is a `hidden beast` number, since 1 + 3 + 1 + 413 + 4 + 3 + 5 + 231 + 0 + 5 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 5399154137664 + 7742189385441 = 2323608^2 + 2782479^2 .
It is not a de Polignac number, because 13141343523105 - 223 = 13141335134497 is a prime.
It is a super-3 number, since 3×131413435231053 (a number of 40 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13141343523105.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 6630652 + ... + 8381421.
It is an arithmetic number, because the mean of its divisors is an integer number (368944236661).
Almost surely, 213141343523105 is an apocalyptic number.
13141343523105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13141343523105 is an abundant number, since it is smaller than the sum of its proper divisors (13422641516487).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13141343523105 is a wasteful number, since it uses less digits than its factorization.
13141343523105 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15012495 (or 15012485 counting only the distinct ones).
The product of its (nonzero) digits is 64800, while the sum is 36.
Adding to 13141343523105 its reverse (50132534314131), we get a palindrome (63273877837236).
The spelling of 13141343523105 in words is "thirteen trillion, one hundred forty-one billion, three hundred forty-three million, five hundred twenty-three thousand, one hundred five".
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