Base | Representation |
---|---|
bin | 10011001010001000100… |
… | …101101000110010011110 |
3 | 11122212020202000211120212 |
4 | 103022020211220302132 |
5 | 133032244144412400 |
6 | 2444452045012422 |
7 | 164055242422355 |
oct | 23121045506236 |
9 | 4585222024525 |
10 | 1316551560350 |
11 | 46838a040494 |
12 | 1931a6554112 |
13 | 971c5219130 |
14 | 47a1589499c |
15 | 243a706b335 |
hex | 13288968c9e |
1316551560350 has 48 divisors (see below), whose sum is σ = 2651886987120. Its totient is φ = 483395596800.
The previous prime is 1316551560271. The next prime is 1316551560367. The reversal of 1316551560350 is 530651556131.
It is a happy number.
It is a super-2 number, since 2×13165515603502 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1316551560298 and 1316551560307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5541371 + ... + 5774070.
It is an arithmetic number, because the mean of its divisors is an integer number (55247645565).
Almost surely, 21316551560350 is an apocalyptic number.
1316551560350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1316551560350 is an abundant number, since it is smaller than the sum of its proper divisors (1335335426770).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1316551560350 is a wasteful number, since it uses less digits than its factorization.
1316551560350 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11315645 (or 11315640 counting only the distinct ones).
The product of its (nonzero) digits is 202500, while the sum is 41.
The spelling of 1316551560350 in words is "one trillion, three hundred sixteen billion, five hundred fifty-one million, five hundred sixty thousand, three hundred fifty".
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