Base | Representation |
---|---|
bin | 1011111110101010101101… |
… | …0011101111000110101110 |
3 | 1201122011021121221021001021 |
4 | 2333222223103233012232 |
5 | 3211244201403312100 |
6 | 44002441425404354 |
7 | 2526406462060432 |
oct | 277525323570656 |
9 | 51564247837037 |
10 | 13171243807150 |
11 | 4218990834660 |
12 | 1588812a996ba |
13 | 747073504360 |
14 | 3376c4d529c2 |
15 | 17c9332c2a1a |
hex | bfaab4ef1ae |
13171243807150 has 48 divisors (see below), whose sum is σ = 28781470399248. Its totient is φ = 4421116800000.
The previous prime is 13171243807079. The next prime is 13171243807213. The reversal of 13171243807150 is 5170834217131.
It is a super-2 number, since 2×131712438071502 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13171243807097 and 13171243807106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 921058851 + ... + 921073150.
It is an arithmetic number, because the mean of its divisors is an integer number (599613966651).
Almost surely, 213171243807150 is an apocalyptic number.
13171243807150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13171243807150 is an abundant number, since it is smaller than the sum of its proper divisors (15610226592098).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13171243807150 is a wasteful number, since it uses less digits than its factorization.
13171243807150 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1842132037 (or 1842132032 counting only the distinct ones).
The product of its (nonzero) digits is 141120, while the sum is 43.
The spelling of 13171243807150 in words is "thirteen trillion, one hundred seventy-one billion, two hundred forty-three million, eight hundred seven thousand, one hundred fifty".
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