Base | Representation |
---|---|
bin | 11000100101100010… |
… | …10001111111110000 |
3 | 1021001220202212000000 |
4 | 30102301101333300 |
5 | 204013122414134 |
6 | 10021445430000 |
7 | 645050352444 |
oct | 142261217760 |
9 | 37056685000 |
10 | 13199810544 |
11 | 5663a49038 |
12 | 268470b300 |
13 | 13248c09ab |
14 | 8d30dc824 |
15 | 523c6ee99 |
hex | 312c51ff0 |
13199810544 has 70 divisors (see below), whose sum is σ = 38344442376. Its totient is φ = 4399932960.
The previous prime is 13199810539. The next prime is 13199810563. The reversal of 13199810544 is 44501899131.
13199810544 is a `hidden beast` number, since 1 + 3 + 1 + 9 + 98 + 10 + 544 = 666.
13199810544 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a self number, because there is not a number n which added to its sum of digits gives 13199810544.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 13 ways as a sum of consecutive naturals, for example, 554172 + ... + 577499.
Almost surely, 213199810544 is an apocalyptic number.
It is an amenable number.
13199810544 is an abundant number, since it is smaller than the sum of its proper divisors (25144631832).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13199810544 is an equidigital number, since it uses as much as digits as its factorization.
13199810544 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1131697 (or 1131676 counting only the distinct ones).
The product of its (nonzero) digits is 155520, while the sum is 45.
The spelling of 13199810544 in words is "thirteen billion, one hundred ninety-nine million, eight hundred ten thousand, five hundred forty-four".
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