Base | Representation |
---|---|
bin | 11110000010010111110110… |
… | …111001010011110000100110 |
3 | 122022202001200100111001101001 |
4 | 132002113312321103300212 |
5 | 114303344404020410400 |
6 | 1144543540325423514 |
7 | 36553142312025565 |
oct | 3602276671236046 |
9 | 568661610431331 |
10 | 132104451341350 |
11 | 3910220190a814 |
12 | 1299688956ab9a |
13 | 589351c8c6a87 |
14 | 2489c64d4dbdc |
15 | 104151748ba6a |
hex | 7825f6e53c26 |
132104451341350 has 24 divisors (see below), whose sum is σ = 256397509040400. Its totient is φ = 50544311817120.
The previous prime is 132104451341299. The next prime is 132104451341381. The reversal of 132104451341350 is 53143154401231.
It is a happy number.
It is a super-3 number, since 3×1321044513413503 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 57436716825 + ... + 57436719124.
It is an arithmetic number, because the mean of its divisors is an integer number (10683229543350).
Almost surely, 2132104451341350 is an apocalyptic number.
132104451341350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132104451341350 is a deficient number, since it is larger than the sum of its proper divisors (124293057699050).
132104451341350 is a wasteful number, since it uses less digits than its factorization.
132104451341350 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 114873435984 (or 114873435979 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 37.
The spelling of 132104451341350 in words is "one hundred thirty-two trillion, one hundred four billion, four hundred fifty-one million, three hundred forty-one thousand, three hundred fifty".
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