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132120003314040 = 23357157285718231
BaseRepresentation
bin11110000010100110010101…
…110111011000000101111000
3122022210112211012021010020120
4132002212111313120011320
5114304123231322022130
61144555031442253240
736554232563434050
oct3602462567300570
9568715735233216
10132120003314040
1139108862567005
12129998a9957220
135894b2a8c4191
14248a8dc5b8560
151041b27983910
hex782995dd8178

132120003314040 has 64 divisors (see below), whose sum is σ = 452982868508160. Its totient is φ = 30198857900160.

The previous prime is 132120003314011. The next prime is 132120003314083. The reversal of 132120003314040 is 40413300021231.

It is a happy number.

It is a super-2 number, since 2×1321200033140402 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a self number, because there is not a number n which added to its sum of digits gives 132120003314040.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 78642858276 + ... + 78642859955.

It is an arithmetic number, because the mean of its divisors is an integer number (7077857320440).

Almost surely, 2132120003314040 is an apocalyptic number.

132120003314040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

132120003314040 is an abundant number, since it is smaller than the sum of its proper divisors (320862865194120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132120003314040 is a wasteful number, since it uses less digits than its factorization.

132120003314040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 157285718252 (or 157285718248 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 132120003314040 its reverse (40413300021231), we get a palindrome (172533303335271).

The spelling of 132120003314040 in words is "one hundred thirty-two trillion, one hundred twenty billion, three million, three hundred fourteen thousand, forty".

Divisors: 1 2 3 4 5 6 7 8 10 12 14 15 20 21 24 28 30 35 40 42 56 60 70 84 105 120 140 168 210 280 420 840 157285718231 314571436462 471857154693 629142872924 786428591155 943714309386 1101000027617 1258285745848 1572857182310 1887428618772 2202000055234 2359285773465 3145714364620 3303000082851 3774857237544 4404000110468 4718571546930 5505000138085 6291428729240 6606000165702 8808000220936 9437143093860 11010000276170 13212000331404 16515000414255 18874286187720 22020000552340 26424000662808 33030000828510 44040001104680 66060001657020 132120003314040