Base | Representation |
---|---|
bin | 11000101001011000… |
… | …00111111110011010 |
3 | 1021011011100220202100 |
4 | 30110230013332122 |
5 | 204044343410320 |
6 | 10024555544230 |
7 | 645621153663 |
oct | 142454077632 |
9 | 37134326670 |
10 | 13232013210 |
11 | 5680143409 |
12 | 269345b076 |
13 | 132b487420 |
14 | 8d74c236a |
15 | 5269d1790 |
hex | 314b07f9a |
13232013210 has 96 divisors (see below), whose sum is σ = 37110423168. Its totient is φ = 3251767680.
The previous prime is 13232013209. The next prime is 13232013217. The reversal of 13232013210 is 1231023231.
13232013210 is a `hidden beast` number, since 1 + 323 + 20 + 1 + 321 + 0 = 666.
It is a super-2 number, since 2×132320132102 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (13232013217) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 729309 + ... + 747231.
It is an arithmetic number, because the mean of its divisors is an integer number (386566908).
Almost surely, 213232013210 is an apocalyptic number.
13232013210 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 13232013210, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18555211584).
13232013210 is an abundant number, since it is smaller than the sum of its proper divisors (23878409958).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13232013210 is a wasteful number, since it uses less digits than its factorization.
13232013210 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18580 (or 18577 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 13232013210 its reverse (1231023231), we get a palindrome (14463036441).
It can be divided in two parts, 132320 and 13210, that added together give a triangular number (145530 = T539).
The spelling of 13232013210 in words is "thirteen billion, two hundred thirty-two million, thirteen thousand, two hundred ten".
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