Base | Representation |
---|---|
bin | 1100000110001010011110… |
… | …0111111100000011101100 |
3 | 1202002110201000210011222221 |
4 | 3001202213213330003230 |
5 | 3220401430414404400 |
6 | 44141541102245124 |
7 | 2541616111212166 |
oct | 301424747740354 |
9 | 52073630704887 |
10 | 13300031013100 |
11 | 4268569859657 |
12 | 15a97755867a4 |
13 | 756259055170 |
14 | 33da2131b936 |
15 | 180e6e91ec1a |
hex | c18a79fc0ec |
13300031013100 has 72 divisors (see below), whose sum is σ = 31081924917680. Its totient is φ = 4910658151680.
The previous prime is 13300031013091. The next prime is 13300031013127. The reversal of 13300031013100 is 131013000331.
13300031013100 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×133000310131002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 64622959 + ... + 64828441.
Almost surely, 213300031013100 is an apocalyptic number.
13300031013100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13300031013100 is an abundant number, since it is smaller than the sum of its proper divisors (17781893904580).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13300031013100 is a wasteful number, since it uses less digits than its factorization.
13300031013100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 255299 (or 255292 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 16.
Adding to 13300031013100 its reverse (131013000331), we get a palindrome (13431044013431).
The spelling of 13300031013100 in words is "thirteen trillion, three hundred billion, thirty-one million, thirteen thousand, one hundred".
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