133001113200 has 120 divisors (see below), whose sum is σ = 426260775600. Its totient is φ = 35449159680.

The previous prime is 133001113187. The next prime is 133001113211. The reversal of 133001113200 is 2311100331.

It is a tau number, because it is divible by the number of its divisors (120).

It is a super-2 number, since 2×133001113200² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 133001113200.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2456016 + ... + 2509584.

It is an arithmetic number, because the mean of its divisors is an integer number (3552173130).

Almost surely, 2^133001113200 is an apocalyptic number.

133001113200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133001113200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (213130387800).

133001113200 is an abundant number, since it is smaller than the sum of its proper divisors (293259662400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133001113200 is a wasteful number, since it uses less digits than its factorization.

133001113200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55659 (or 55648 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 133001113200 its reverse (2311100331), we get a palindrome (135312213531).

The spelling of 133001113200 in words is "one hundred thirty-three billion, one million, one hundred thirteen thousand, two hundred".