Base | Representation |
---|---|
bin | 11110001111100100010001… |
… | …010010110011010011010100 |
3 | 122102221201222111201120202122 |
4 | 132033210101102303103110 |
5 | 114413223244334044340 |
6 | 1150520245353555112 |
7 | 40005510566211653 |
oct | 3617442122632324 |
9 | 572851874646678 |
10 | 133011132331220 |
11 | 39421782676140 |
12 | 12b02547115a98 |
13 | 592ab85563310 |
14 | 24bbab777119a |
15 | 1059dd12badb5 |
hex | 78f9114b34d4 |
133011132331220 has 96 divisors (see below), whose sum is σ = 328867974965376. Its totient is φ = 44550244569600.
The previous prime is 133011132331183. The next prime is 133011132331289. The reversal of 133011132331220 is 22133231110331.
It is a super-2 number, since 2×1330111323312202 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (26).
It is a self number, because there is not a number n which added to its sum of digits gives 133011132331220.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 49123394 + ... + 51760313.
It is an arithmetic number, because the mean of its divisors is an integer number (3425708072556).
Almost surely, 2133011132331220 is an apocalyptic number.
133011132331220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133011132331220 is an abundant number, since it is smaller than the sum of its proper divisors (195856842634156).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133011132331220 is a wasteful number, since it uses less digits than its factorization.
133011132331220 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 100884201 (or 100884199 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 26.
Adding to 133011132331220 its reverse (22133231110331), we get a palindrome (155144363441551).
It can be divided in two parts, 133011 and 132331220, that added together give a palindrome (132464231).
The spelling of 133011132331220 in words is "one hundred thirty-three trillion, eleven billion, one hundred thirty-two million, three hundred thirty-one thousand, two hundred twenty".
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