Base | Representation |
---|---|
bin | 11110001111100101000110… |
… | …111011100101000000001000 |
3 | 122102221211022020000022111110 |
4 | 132033211012323211000020 |
5 | 114413232120221304000 |
6 | 1150520514541330320 |
7 | 40005542104116003 |
oct | 3617450673450010 |
9 | 572854266008443 |
10 | 133012032213000 |
11 | 394220a4627696 |
12 | 12b027585669a0 |
13 | 592ac99b17c45 |
14 | 24bbb6109a53a |
15 | 1059e352c2850 |
hex | 78f946ee5008 |
133012032213000 has 128 divisors (see below), whose sum is σ = 439409160702720. Its totient is φ = 33383411993600.
The previous prime is 133012032212933. The next prime is 133012032213013. The reversal of 133012032213000 is 312230210331.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1303988532 + ... + 1304090531.
It is an arithmetic number, because the mean of its divisors is an integer number (3432884067990).
Almost surely, 2133012032213000 is an apocalyptic number.
133012032213000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133012032213000 is an abundant number, since it is smaller than the sum of its proper divisors (306397128489720).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133012032213000 is a wasteful number, since it uses less digits than its factorization.
133012032213000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2608079104 (or 2608079090 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 133012032213000 its reverse (312230210331), we get a palindrome (133324262423331).
The spelling of 133012032213000 in words is "one hundred thirty-three trillion, twelve billion, thirty-two million, two hundred thirteen thousand".
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