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133144343231400 = 23325273969079573
BaseRepresentation
bin11110010001100000010101…
…010010000011101110101000
3122110102110211012112110101100
4132101200111102003232220
5114422414103331401100
61151101400013521400
740021234642165224
oct3621402522035650
9573373735473340
10133144343231400
1139473220763086
1212b243231a3260
13593a5c4721b87
1424c4313461784
15105d5cae82400
hex791815483ba8

133144343231400 has 72 divisors (see below), whose sum is σ = 447143086024830. Its totient is φ = 35505158194560.

The previous prime is 133144343231381. The next prime is 133144343231443. The reversal of 133144343231400 is 4132343441331.

133144343231400 is a `hidden beast` number, since 1 + 3 + 3 + 1 + 44 + 343 + 231 + 40 + 0 = 666.

It can be written as a sum of positive squares in 3 ways, for example, as 52008530349636 + 81135812881764 = 7211694^2 + 9007542^2 .

It is a tau number, because it is divible by the number of its divisors (72).

It is a super-2 number, since 2×1331443432314002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is an unprimeable number.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 36984537987 + ... + 36984541586.

Almost surely, 2133144343231400 is an apocalyptic number.

133144343231400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

133144343231400 is an abundant number, since it is smaller than the sum of its proper divisors (313998742793430).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133144343231400 is a wasteful number, since it uses less digits than its factorization.

133144343231400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 73969079595 (or 73969079583 counting only the distinct ones).

The product of its (nonzero) digits is 124416, while the sum is 36.

Adding to 133144343231400 its reverse (4132343441331), we get a palindrome (137276686672731).

The spelling of 133144343231400 in words is "one hundred thirty-three trillion, one hundred forty-four billion, three hundred forty-three million, two hundred thirty-one thousand, four hundred".

Divisors: 1 2 3 4 5 6 8 9 10 12 15 18 20 24 25 30 36 40 45 50 60 72 75 90 100 120 150 180 200 225 300 360 450 600 900 1800 73969079573 147938159146 221907238719 295876318292 369845397865 443814477438 591752636584 665721716157 739690795730 887628954876 1109536193595 1331443432314 1479381591460 1775257909752 1849226989325 2219072387190 2662886864628 2958763182920 3328608580785 3698453978650 4438144774380 5325773729256 5547680967975 6657217161570 7396907957300 8876289548760 11095361935950 13314434323140 14793815914600 16643042903925 22190723871900 26628868646280 33286085807850 44381447743800 66572171615700 133144343231400