Base | Representation |
---|---|
bin | 10011011000101000100… |
… | …110011000100001001100 |
3 | 11201100102210200221111101 |
4 | 103120220212120201030 |
5 | 133311140434343200 |
6 | 2455545024232444 |
7 | 165146125530511 |
oct | 23305046304114 |
9 | 4640383627441 |
10 | 1332121012300 |
11 | 473a49646151 |
12 | 19621076b724 |
13 | 98806a264b0 |
14 | 4869158d308 |
15 | 249b8d6726a |
hex | 1362899884c |
1332121012300 has 72 divisors (see below), whose sum is σ = 3113370325296. Its totient is φ = 491811720960.
The previous prime is 1332121012289. The next prime is 1332121012303. The reversal of 1332121012300 is 32101212331.
It is a super-2 number, since 2×13321210123002 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1332121012303) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 14883282 + ... + 14972518.
It is an arithmetic number, because the mean of its divisors is an integer number (43241254518).
Almost surely, 21332121012300 is an apocalyptic number.
1332121012300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1332121012300 is an abundant number, since it is smaller than the sum of its proper divisors (1781249312996).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1332121012300 is a wasteful number, since it uses less digits than its factorization.
1332121012300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 100747 (or 100740 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 1332121012300 its reverse (32101212331), we get a palindrome (1364222224631).
The spelling of 1332121012300 in words is "one trillion, three hundred thirty-two billion, one hundred twenty-one million, twelve thousand, three hundred".
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