Base | Representation |
---|---|
bin | 1100001100001101111010… |
… | …1000011111111100110100 |
3 | 1202110102011010002201200220 |
4 | 3003003132220133330310 |
5 | 3224102424434401400 |
6 | 44301421112334340 |
7 | 2552260302440025 |
oct | 303033650377464 |
9 | 52412133081626 |
10 | 13404033122100 |
11 | 42a8689289455 |
12 | 160595b6a43b0 |
13 | 762cc1a4422a |
14 | 344a89ac0c4c |
15 | 183a0a1997a0 |
hex | c30dea1ff34 |
13404033122100 has 72 divisors (see below), whose sum is σ = 38815455839328. Its totient is φ = 3571356297600.
The previous prime is 13404033122093. The next prime is 13404033122167. The reversal of 13404033122100 is 122133040431.
It is a happy number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 18726459 + ... + 19429058.
It is an arithmetic number, because the mean of its divisors is an integer number (539103553324).
Almost surely, 213404033122100 is an apocalyptic number.
13404033122100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13404033122100 is an abundant number, since it is smaller than the sum of its proper divisors (25411422717228).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13404033122100 is a wasteful number, since it uses less digits than its factorization.
13404033122100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38156705 (or 38156698 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 13404033122100 its reverse (122133040431), we get a palindrome (13526166162531).
The spelling of 13404033122100 in words is "thirteen trillion, four hundred four billion, thirty-three million, one hundred twenty-two thousand, one hundred".
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