Base | Representation |
---|---|
bin | 1100001101011001100110… |
… | …1111101000101001010100 |
3 | 1202112100121012000220022210 |
4 | 3003112121233220221110 |
5 | 3224421033130420200 |
6 | 44315021240553420 |
7 | 2553606650656005 |
oct | 303263157505124 |
9 | 52470535026283 |
10 | 13424352201300 |
11 | 4306265933397 |
12 | 1609890482870 |
13 | 764bac569c11 |
14 | 345a565051ac |
15 | 1842e8e42650 |
hex | c3599be8a54 |
13424352201300 has 72 divisors (see below), whose sum is σ = 40885395493600. Its totient is φ = 3391415291520.
The previous prime is 13424352201289. The next prime is 13424352201317. The reversal of 13424352201300 is 310225342431.
13424352201300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1177569055 + ... + 1177580454.
Almost surely, 213424352201300 is an apocalyptic number.
13424352201300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13424352201300 is an abundant number, since it is smaller than the sum of its proper divisors (27461043292300).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13424352201300 is a wasteful number, since it uses less digits than its factorization.
13424352201300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2355149545 (or 2355149538 counting only the distinct ones).
The product of its (nonzero) digits is 17280, while the sum is 30.
Adding to 13424352201300 its reverse (310225342431), we get a palindrome (13734577543731).
The spelling of 13424352201300 in words is "thirteen trillion, four hundred twenty-four billion, three hundred fifty-two million, two hundred one thousand, three hundred".
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