13434110000 has 100 divisors (see below), whose sum is σ = 32612798064. Its totient is φ = 5359200000.

The previous prime is 13434109991. The next prime is 13434110033. The reversal of 13434110000 is 1143431.

It is a tau number, because it is divible by the number of its divisors (100).

It is a super-2 number, since 2×13434110000² (a number of 21 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 4208405 + ... + 4211595.

Almost surely, 2^13434110000 is an apocalyptic number.

13434110000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13434110000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16306399032).

13434110000 is an abundant number, since it is smaller than the sum of its proper divisors (19178688064).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13434110000 is an equidigital number, since it uses as much as digits as its factorization.

13434110000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3640 (or 3619 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 13434110000 its reverse (1143431), we get a palindrome (13435253431).

The spelling of 13434110000 in words is "thirteen billion, four hundred thirty-four million, one hundred ten thousand".