1344301420224 has 112 divisors (see below), whose sum is σ = 4070079711488. Its totient is φ = 383597779968.

The previous prime is 1344301420153. The next prime is 1344301420247. The reversal of 1344301420224 is 4220241034431.

It is a tau number, because it is divible by the number of its divisors (112).

It is a junction number, because it is equal to n+sod(n) for n = 1344301420191 and 1344301420200.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 422262 + ... + 1693194.

It is an arithmetic number, because the mean of its divisors is an integer number (36339997424).

Almost surely, 2^{1344301420224} is an apocalyptic number.

1344301420224 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1344301420224, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2035039855744).

1344301420224 is an abundant number, since it is smaller than the sum of its proper divisors (2725778291264).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1344301420224 is a wasteful number, since it uses less digits than its factorization.

1344301420224 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1271742 (or 1271732 counting only the distinct ones).

The product of its (nonzero) digits is 18432, while the sum is 30.

Adding to 1344301420224 its reverse (4220241034431), we get a palindrome (5564542454655).

The spelling of 1344301420224 in words is "one trillion, three hundred forty-four billion, three hundred one million, four hundred twenty thousand, two hundred twenty-four".