Base | Representation |
---|---|
bin | 111110100110011011… |
… | …1011111011100000000 |
3 | 110211222220112112012122 |
4 | 1331030313133130000 |
5 | 4200310000220110 |
6 | 141431414343412 |
7 | 12466250520416 |
oct | 1751467373400 |
9 | 424886475178 |
10 | 134433601280 |
11 | 52016299420 |
12 | 2207965ab68 |
13 | c8a55a0a44 |
14 | 671424d2b6 |
15 | 376c1d8255 |
hex | 1f4cddf700 |
134433601280 has 72 divisors (see below), whose sum is σ = 351284202864. Its totient is φ = 48884940800.
The previous prime is 134433601271. The next prime is 134433601297. The reversal of 134433601280 is 82106334431.
It is a super-2 number, since 2×1344336012802 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 134433601280.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4759841 + ... + 4788000.
It is an arithmetic number, because the mean of its divisors is an integer number (4878947262).
Almost surely, 2134433601280 is an apocalyptic number.
134433601280 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
134433601280 is an abundant number, since it is smaller than the sum of its proper divisors (216850601584).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134433601280 is an equidigital number, since it uses as much as digits as its factorization.
134433601280 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9547873 (or 9547859 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 35.
The spelling of 134433601280 in words is "one hundred thirty-four billion, four hundred thirty-three million, six hundred one thousand, two hundred eighty".
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