13550143122040 has 128 divisors (see below), whose sum is σ = 36900808104960. Its totient is φ = 4377448525824.

The previous prime is 13550143122011. The next prime is 13550143122071. The reversal of 13550143122040 is 4022134105531.

It is a junction number, because it is equal to n+sod(n) for n = 13550143121993 and 13550143122011.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15270457 + ... + 16133416.

It is an arithmetic number, because the mean of its divisors is an integer number (288287563320).

Almost surely, 2^{13550143122040} is an apocalyptic number.

13550143122040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13550143122040 is an abundant number, since it is smaller than the sum of its proper divisors (23350664982920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13550143122040 is a wasteful number, since it uses less digits than its factorization.

13550143122040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31403981 (or 31403977 counting only the distinct ones).

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 13550143122040 its reverse (4022134105531), we get a palindrome (17572277227571).

The spelling of 13550143122040 in words is "thirteen trillion, five hundred fifty billion, one hundred forty-three million, one hundred twenty-two thousand, forty".