Base | Representation |
---|---|
bin | 11111000001100100101011… |
… | …010010110001010010101000 |
3 | 122220010020221211110201011002 |
4 | 133001210223102301102220 |
5 | 120341024031321224100 |
6 | 1202111045143054132 |
7 | 40512003204446045 |
oct | 3701445322612250 |
9 | 586106854421132 |
10 | 136447542367400 |
11 | 3a527094539300 |
12 | 13378545a41348 |
13 | 5b19c42aa8b54 |
14 | 259a14c2dc1cc |
15 | 10b94a8b622d5 |
hex | 7c192b4b14a8 |
136447542367400 has 144 divisors (see below), whose sum is σ = 353116366814400. Its totient is φ = 48989220508800.
The previous prime is 136447542367369. The next prime is 136447542367427. The reversal of 136447542367400 is 4763245744631.
136447542367400 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×1364475423674003 (a number of 43 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 33773822 + ... + 37597421.
Almost surely, 2136447542367400 is an apocalyptic number.
136447542367400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
136447542367400 is an abundant number, since it is smaller than the sum of its proper divisors (216668824447000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
136447542367400 is a wasteful number, since it uses less digits than its factorization.
136447542367400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71371360 (or 71371340 counting only the distinct ones).
The product of its (nonzero) digits is 40642560, while the sum is 56.
The spelling of 136447542367400 in words is "one hundred thirty-six trillion, four hundred forty-seven billion, five hundred forty-two million, three hundred sixty-seven thousand, four hundred".
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