Base | Representation |
---|---|
bin | 1100101111000110011001… |
… | …1001110000100010111000 |
3 | 1211120200222211221012000110 |
4 | 3023301212121300202320 |
5 | 3313412240210212212 |
6 | 45441011002104320 |
7 | 2643464053040115 |
oct | 313614631604270 |
9 | 54520884835013 |
10 | 14003311413432 |
11 | 4509853255600 |
12 | 16a1b287ab0a0 |
13 | 7a7678001293 |
14 | 365a9a17990c |
15 | 1943d19a7a3c |
hex | cbc666708b8 |
14003311413432 has 48 divisors (see below), whose sum is σ = 38480173933320. Its totient is φ = 4243427700160.
The previous prime is 14003311413367. The next prime is 14003311413437. The reversal of 14003311413432 is 23431411330041.
It is a self number, because there is not a number n which added to its sum of digits gives 14003311413432.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14003311413437) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2411035563 + ... + 2411041370.
Almost surely, 214003311413432 is an apocalyptic number.
14003311413432 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
14003311413432 is an abundant number, since it is smaller than the sum of its proper divisors (24476862519888).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14003311413432 is a wasteful number, since it uses less digits than its factorization.
14003311413432 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4822076964 (or 4822076949 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 14003311413432 its reverse (23431411330041), we get a palindrome (37434722743473).
The spelling of 14003311413432 in words is "fourteen trillion, three billion, three hundred eleven million, four hundred thirteen thousand, four hundred thirty-two".
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