Base | Representation |
---|---|
bin | 10100100010001000100… |
… | …111100011011101000100 |
3 | 11222220010220020011001121 |
4 | 110202020213203131010 |
5 | 141104303040441200 |
6 | 3000120133003324 |
7 | 203641630344211 |
oct | 24421047433504 |
9 | 4886126204047 |
10 | 1411041343300 |
11 | 4a44680639a6 |
12 | 1a9576a83544 |
13 | a30a32785c4 |
14 | 4c41ab9cb08 |
15 | 26a87668e1a |
hex | 148889e3744 |
1411041343300 has 72 divisors (see below), whose sum is σ = 3115188240192. Its totient is φ = 554622864000.
The previous prime is 1411041343291. The next prime is 1411041343301. The reversal of 1411041343300 is 33431401141.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is not an unprimeable number, because it can be changed into a prime (1411041343301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6176919 + ... + 6401281.
It is an arithmetic number, because the mean of its divisors is an integer number (43266503336).
Almost surely, 21411041343300 is an apocalyptic number.
1411041343300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1411041343300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1557594120096).
1411041343300 is an abundant number, since it is smaller than the sum of its proper divisors (1704146896892).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1411041343300 is a wasteful number, since it uses less digits than its factorization.
1411041343300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 225469 (or 225462 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1411041343300 its reverse (33431401141), we get a palindrome (1444472744441).
The spelling of 1411041343300 in words is "one trillion, four hundred eleven billion, forty-one million, three hundred forty-three thousand, three hundred".
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