141113435520 has 64 divisors (see below), whose sum is σ = 449799081840. Its totient is φ = 37630248960.

The previous prime is 141113435509. The next prime is 141113435527. The reversal of 141113435520 is 25534311141.

It is a tau number, because it is divible by the number of its divisors (64).

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141113435527) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 36746371 + ... + 36750210.

Almost surely, 2^141113435520 is an apocalyptic number.

141113435520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

141113435520 is an abundant number, since it is smaller than the sum of its proper divisors (308685646320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141113435520 is an equidigital number, since it uses as much as digits as its factorization.

141113435520 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 73496603 (or 73496591 counting only the distinct ones).

The product of its (nonzero) digits is 7200, while the sum is 30.

Adding to 141113435520 its reverse (25534311141), we get a palindrome (166647746661).

The spelling of 141113435520 in words is "one hundred forty-one billion, one hundred thirteen million, four hundred thirty-five thousand, five hundred twenty".