Base | Representation |
---|---|
bin | 1100110101011111011001… |
… | …0110000011100101001111 |
3 | 1211222012101020112220100222 |
4 | 3031113312112003211033 |
5 | 3322212112214404320 |
6 | 50003245140141555 |
7 | 2654431534203632 |
oct | 315276626034517 |
9 | 54865336486328 |
10 | 14113100544335 |
11 | 4551372369631 |
12 | 16bb2689978bb |
13 | 7b4b23909870 |
14 | 36b11334bc19 |
15 | 1971aa2ea825 |
hex | cd5f658394f |
14113100544335 has 64 divisors (see below), whose sum is σ = 19161695266560. Its totient is φ = 9900686315520.
The previous prime is 14113100544281. The next prime is 14113100544383. The reversal of 14113100544335 is 53344500131141.
It is a happy number.
It is not a de Polignac number, because 14113100544335 - 212 = 14113100540239 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14113100544295 and 14113100544304.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 541943915 + ... + 541969955.
It is an arithmetic number, because the mean of its divisors is an integer number (299401488540).
Almost surely, 214113100544335 is an apocalyptic number.
14113100544335 is a deficient number, since it is larger than the sum of its proper divisors (5048594722225).
14113100544335 is a wasteful number, since it uses less digits than its factorization.
14113100544335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28548.
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 14113100544335 its reverse (53344500131141), we get a palindrome (67457600675476).
The spelling of 14113100544335 in words is "fourteen trillion, one hundred thirteen billion, one hundred million, five hundred forty-four thousand, three hundred thirty-five".
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