141132014000 has 40 divisors (see below), whose sum is σ = 341257214688. Its totient is φ = 56452804800.

The previous prime is 141132013999. The next prime is 141132014039. The reversal of 141132014000 is 410231141.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (40).

It is a super-3 number, since 3×141132014000³ (a number of 34 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 141132014000.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35281004 + ... + 35285003.

Almost surely, 2^141132014000 is an apocalyptic number.

141132014000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

141132014000 is an abundant number, since it is smaller than the sum of its proper divisors (200125200688).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141132014000 is an equidigital number, since it uses as much as digits as its factorization.

141132014000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70566030 (or 70566014 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 141132014000 its reverse (410231141), we get a palindrome (141542245141).

The spelling of 141132014000 in words is "one hundred forty-one billion, one hundred thirty-two million, fourteen thousand".