Base | Representation |
---|---|
bin | 110101110111… |
… | …100101010100 |
3 | 222120102210010 |
4 | 311313211110 |
5 | 12103340200 |
6 | 1222400220 |
7 | 231012654 |
oct | 65674524 |
9 | 28512703 |
10 | 14121300 |
11 | 7a755a6 |
12 | 4890070 |
13 | 2c056cb |
14 | 1c38364 |
15 | 138e150 |
hex | d77954 |
14121300 has 72 divisors (see below), whose sum is σ = 41344576. Its totient is φ = 3720960.
The previous prime is 14121299. The next prime is 14121301. The reversal of 14121300 is 312141.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (14121299) and next prime (14121301).
It is a super-2 number, since 2×141213002 = 398822227380000, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14121301) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 30672 + ... + 31128.
Almost surely, 214121300 is an apocalyptic number.
14121300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 14121300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20672288).
14121300 is an abundant number, since it is smaller than the sum of its proper divisors (27223276).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14121300 is a wasteful number, since it uses less digits than its factorization.
14121300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 577 (or 570 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 12.
The square root of 14121300 is about 3757.8318216759. The cubic root of 14121300 is about 241.7082977559.
Adding to 14121300 its reverse (312141), we get a palindrome (14433441).
The spelling of 14121300 in words is "fourteen million, one hundred twenty-one thousand, three hundred".
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