Base | Representation |
---|---|
bin | 1000010010011110111… |
… | …0001100010100000111 |
3 | 111121120010100211221011 |
4 | 2010213232030110013 |
5 | 4313113441410010 |
6 | 145230125303051 |
7 | 13200545633524 |
oct | 2044756142407 |
9 | 447503324834 |
10 | 142400341255 |
11 | 5543430a047 |
12 | 23721704a87 |
13 | 10574c6a073 |
14 | 6c6c33a14b |
15 | 3a86813a8a |
hex | 2127b8c507 |
142400341255 has 64 divisors (see below), whose sum is σ = 190811013120. Its totient is φ = 101637043200.
The previous prime is 142400341247. The next prime is 142400341273. The reversal of 142400341255 is 552143004241.
It is not a de Polignac number, because 142400341255 - 23 = 142400341247 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 14078650 + ... + 14088760.
It is an arithmetic number, because the mean of its divisors is an integer number (2981422080).
Almost surely, 2142400341255 is an apocalyptic number.
142400341255 is a deficient number, since it is larger than the sum of its proper divisors (48410671865).
142400341255 is a wasteful number, since it uses less digits than its factorization.
142400341255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10312.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 142400341255 its reverse (552143004241), we get a palindrome (694543345496).
The spelling of 142400341255 in words is "one hundred forty-two billion, four hundred million, three hundred forty-one thousand, two hundred fifty-five".
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