Base | Representation |
---|---|
bin | 1101000011100001100100… |
… | …0000000100100100000000 |
3 | 1212211020200212222222221112 |
4 | 3100320121000010210000 |
5 | 3340134400214333240 |
6 | 50310121205342452 |
7 | 3011025314102630 |
oct | 320703100044400 |
9 | 55736625888845 |
10 | 14354200152320 |
11 | 46346448555a6 |
12 | 1739b34707a28 |
13 | 801797a526b2 |
14 | 378a65a766c0 |
15 | 19d5bba61665 |
hex | d0e19004900 |
14354200152320 has 72 divisors (see below), whose sum is σ = 39294622941504. Its totient is φ = 4921440049152.
The previous prime is 14354200152269. The next prime is 14354200152337. The reversal of 14354200152320 is 2325100245341.
It is a super-2 number, since 2×143542001523202 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (32).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 801006674 + ... + 801024593.
Almost surely, 214354200152320 is an apocalyptic number.
14354200152320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14354200152320 is an abundant number, since it is smaller than the sum of its proper divisors (24940422789184).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14354200152320 is an equidigital number, since it uses as much as digits as its factorization.
14354200152320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1602031295 (or 1602031281 counting only the distinct ones).
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 14354200152320 its reverse (2325100245341), we get a palindrome (16679300397661).
The spelling of 14354200152320 in words is "fourteen trillion, three hundred fifty-four billion, two hundred million, one hundred fifty-two thousand, three hundred twenty".
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