Base | Representation |
---|---|
bin | 10100111101100001000… |
… | …100010000110000000100 |
3 | 12002201000220210021020020 |
4 | 110331201010100300010 |
5 | 142100011243120200 |
6 | 3021421414535140 |
7 | 206032336444614 |
oct | 24754104206004 |
9 | 5081026707206 |
10 | 1440442551300 |
11 | 5059852a4705 |
12 | 1b32013674b0 |
13 | a5aaa5788bc |
14 | 4da09896a44 |
15 | 27708912ea0 |
hex | 14f61110c04 |
1440442551300 has 72 divisors (see below), whose sum is σ = 4186040472096. Its totient is φ = 382425845760.
The previous prime is 1440442551221. The next prime is 1440442551349. The reversal of 1440442551300 is 31552440441.
It is a happy number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 10507837 + ... + 10644036.
Almost surely, 21440442551300 is an apocalyptic number.
1440442551300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1440442551300 is an abundant number, since it is smaller than the sum of its proper divisors (2745597920796).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1440442551300 is a wasteful number, since it uses less digits than its factorization.
1440442551300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21152117 (or 21152110 counting only the distinct ones).
The product of its (nonzero) digits is 38400, while the sum is 33.
Adding to 1440442551300 its reverse (31552440441), we get a palindrome (1471994991741).
The spelling of 1440442551300 in words is "one trillion, four hundred forty billion, four hundred forty-two million, five hundred fifty-one thousand, three hundred".
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