Base | Representation |
---|---|
bin | 10100111111111010010… |
… | …111001101001001000100 |
3 | 12002221200011020022100001 |
4 | 110333322113031021010 |
5 | 142120243143300200 |
6 | 3022524531131044 |
7 | 206153146200211 |
oct | 24777227151104 |
9 | 5087604208301 |
10 | 1443014431300 |
11 | 506a85033172 |
12 | 1b37ba743a84 |
13 | a60ca3544a0 |
14 | 4dbb1298b08 |
15 | 278095db76a |
hex | 14ffa5cd244 |
1443014431300 has 36 divisors (see below), whose sum is σ = 3372213727876. Its totient is φ = 532805328000.
The previous prime is 1443014431291. The next prime is 1443014431301. The reversal of 1443014431300 is 31344103441.
It is a happy number.
It can be written as a sum of positive squares in 6 ways, for example, as 387085554244 + 1055928877056 = 622162^2 + 1027584^2 .
It is not an unprimeable number, because it can be changed into a prime (1443014431301) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 555004251 + ... + 555006850.
Almost surely, 21443014431300 is an apocalyptic number.
1443014431300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1443014431300 is an abundant number, since it is smaller than the sum of its proper divisors (1929199296576).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1443014431300 is a wasteful number, since it uses less digits than its factorization.
1443014431300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1110011128 (or 1110011121 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 1443014431300 its reverse (31344103441), we get a palindrome (1474358534741).
The spelling of 1443014431300 in words is "one trillion, four hundred forty-three billion, fourteen million, four hundred thirty-one thousand, three hundred".
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