Base | Representation |
---|---|
bin | 1000111000010000111… |
… | …1010001011001100100 |
3 | 112120201221112102101112 |
4 | 2032010033101121210 |
5 | 4444401331420200 |
6 | 154024350044152 |
7 | 14010100304501 |
oct | 2160417213144 |
9 | 476657472345 |
10 | 152542451300 |
11 | 59769267478 |
12 | 256921a9658 |
13 | 11500223105 |
14 | 75512d24a8 |
15 | 3e7bde3535 |
hex | 23843d1664 |
152542451300 has 72 divisors (see below), whose sum is σ = 334582413480. Its totient is φ = 60360832000.
The previous prime is 152542451291. The next prime is 152542451317. The reversal of 152542451300 is 3154245251.
It can be written as a sum of positive squares in 12 ways, for example, as 26927497216 + 125614954084 = 164096^2 + 354422^2 .
It is a super-2 number, since 2×1525424513002 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 13013042 + ... + 13024758.
It is an arithmetic number, because the mean of its divisors is an integer number (4646977965).
Almost surely, 2152542451300 is an apocalyptic number.
152542451300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 152542451300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (167291206740).
152542451300 is an abundant number, since it is smaller than the sum of its proper divisors (182039962180).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
152542451300 is a wasteful number, since it uses less digits than its factorization.
152542451300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13121 (or 13114 counting only the distinct ones).
The product of its (nonzero) digits is 24000, while the sum is 32.
Adding to 152542451300 its reverse (3154245251), we get a palindrome (155696696551).
The spelling of 152542451300 in words is "one hundred fifty-two billion, five hundred forty-two million, four hundred fifty-one thousand, three hundred".
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