Base | Representation |
---|---|
bin | 1010000010001111011… |
… | …1110101011111001000 |
3 | 121110222220000102010200 |
4 | 2200203313311133020 |
5 | 10311034014001100 |
6 | 211111045412200 |
7 | 15312150223656 |
oct | 2404367653710 |
9 | 543886012120 |
10 | 172400531400 |
11 | 67129672a19 |
12 | 294b470a060 |
13 | 1334639a876 |
14 | 84b67d3dd6 |
15 | 4740478e00 |
hex | 2823df57c8 |
172400531400 has 72 divisors (see below), whose sum is σ = 578978457330. Its totient is φ = 45973474560.
The previous prime is 172400531357. The next prime is 172400531467. The reversal of 172400531400 is 4135004271.
172400531400 is a `hidden beast` number, since 1 + 72 + 400 + 53 + 140 + 0 = 666.
It can be written as a sum of positive squares in 3 ways, for example, as 74106995076 + 98293536324 = 272226^2 + 313518^2 .
It is a tau number, because it is divible by the number of its divisors (72).
It is an unprimeable number.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 47887237 + ... + 47890836.
Almost surely, 2172400531400 is an apocalyptic number.
172400531400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
172400531400 is an abundant number, since it is smaller than the sum of its proper divisors (406577925930).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
172400531400 is a wasteful number, since it uses less digits than its factorization.
172400531400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 95778095 (or 95778083 counting only the distinct ones).
The product of its (nonzero) digits is 3360, while the sum is 27.
Adding to 172400531400 its reverse (4135004271), we get a palindrome (176535535671).
The spelling of 172400531400 in words is "one hundred seventy-two billion, four hundred million, five hundred thirty-one thousand, four hundred".
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