Base | Representation |
---|---|
bin | 11101001001000000001… |
… | …011100011101010111111 |
3 | 21002102212212100222021100 |
4 | 131021000023203222333 |
5 | 230302141033001310 |
6 | 4131541132304143 |
7 | 264451412111160 |
oct | 35110013435277 |
9 | 7072785328240 |
10 | 2002531531455 |
11 | 7022a5930944 |
12 | 28412b912053 |
13 | 116ab7b83890 |
14 | 6ccccb8b767 |
15 | 37155385ec0 |
hex | 1d2402e3abf |
2002531531455 has 48 divisors (see below), whose sum is σ = 4272067275840. Its totient is φ = 845024292864.
The previous prime is 2002531531381. The next prime is 2002531531459. The reversal of 2002531531455 is 5541351352002.
2002531531455 is a `hidden beast` number, since 2 + 0 + 0 + 2 + 53 + 153 + 1 + 455 = 666.
It is not a de Polignac number, because 2002531531455 - 210 = 2002531530431 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2002531531459) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 244505250 + ... + 244513439.
It is an arithmetic number, because the mean of its divisors is an integer number (89001401580).
Almost surely, 22002531531455 is an apocalyptic number.
2002531531455 is an abundant number, since it is smaller than the sum of its proper divisors (2269535744385).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2002531531455 is a wasteful number, since it uses less digits than its factorization.
2002531531455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 489018720 (or 489018717 counting only the distinct ones).
The product of its (nonzero) digits is 90000, while the sum is 36.
Adding to 2002531531455 its reverse (5541351352002), we get a palindrome (7543882883457).
The spelling of 2002531531455 in words is "two trillion, two billion, five hundred thirty-one million, five hundred thirty-one thousand, four hundred fifty-five".
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