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20132100023 = 710150395651
BaseRepresentation
bin10010101111111101…
…110111011110110111
31220222001002122102012
4102233331313132313
5312212304200043
613125404434435
71311615012110
oct225775673667
956861078365
1020132100023
1185a10557a2
123a9a248a1b
131b8ab7a229
14d8da71207
157cc661a18
hex4aff777b7

20132100023 has 16 divisors (see below), whose sum is σ = 23244641280. Its totient is φ = 17078820000.

The previous prime is 20132100017. The next prime is 20132100041. The reversal of 20132100023 is 32000123102.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 20132100023 - 210 = 20132098999 is a prime.

It is a super-3 number, since 3×201321000233 (a number of 32 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20132099980 and 20132100007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20132100013) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3559748 + ... + 3565398.

It is an arithmetic number, because the mean of its divisors is an integer number (1452790080).

Almost surely, 220132100023 is an apocalyptic number.

20132100023 is a deficient number, since it is larger than the sum of its proper divisors (3112541257).

20132100023 is a wasteful number, since it uses less digits than its factorization.

20132100023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10798.

The product of its (nonzero) digits is 72, while the sum is 14.

Adding to 20132100023 its reverse (32000123102), we get a palindrome (52132223125).

The spelling of 20132100023 in words is "twenty billion, one hundred thirty-two million, one hundred thousand, twenty-three".

Divisors: 1 7 101 707 5039 5651 35273 39557 508939 570751 3562573 3995257 28475389 199327723 2876014289 20132100023