Base | Representation |
---|---|
bin | 101101110100101101100011… |
… | …001010011100110011010000 |
3 | 222102120111112211111022201210 |
4 | 231310231203022130303100 |
5 | 202403414440003122000 |
6 | 1552343344241100120 |
7 | 60310244441143122 |
oct | 5564554312346320 |
9 | 872514484438653 |
10 | 201534414114000 |
11 | 592402a0859970 |
12 | 1a72a877627640 |
13 | 885b7c9402846 |
14 | 37aa463a49212 |
15 | 184758c838350 |
hex | b74b6329ccd0 |
201534414114000 has 160 divisors (see below), whose sum is σ = 708814855981440. Its totient is φ = 48856827648000.
The previous prime is 201534414113993. The next prime is 201534414114013. The reversal of 201534414114000 is 411414435102.
201534414114000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×2015344141140002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1526709865 + ... + 1526841864.
It is an arithmetic number, because the mean of its divisors is an integer number (4430092849884).
Almost surely, 2201534414114000 is an apocalyptic number.
201534414114000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
201534414114000 is an abundant number, since it is smaller than the sum of its proper divisors (507280441867440).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
201534414114000 is a wasteful number, since it uses less digits than its factorization.
201534414114000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3053551766 (or 3053551750 counting only the distinct ones).
The product of its (nonzero) digits is 7680, while the sum is 30.
Adding to 201534414114000 its reverse (411414435102), we get a palindrome (201945828549102).
The spelling of 201534414114000 in words is "two hundred one trillion, five hundred thirty-four billion, four hundred fourteen million, one hundred fourteen thousand".
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