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202031211300 = 223521739613963
BaseRepresentation
bin1011110000100111111…
…1111010001100100100
3201022110220100220120120
42330021333322030210
511302224442230200
6232451210001540
720411343650562
oct2741177721444
9638426326516
10202031211300
1178754396326
12331a3a162b0
13160890a3959
149ac7b82a32
1553c694e9a0
hex2f09ffa324

202031211300 has 72 divisors (see below), whose sum is σ = 618928573536. Its totient is φ = 50705871360.

The previous prime is 202031211287. The next prime is 202031211301. The reversal of 202031211300 is 3112130202.

202031211300 is digitally balanced in base 7, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×2020312113002 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 202031211300.

It is not an unprimeable number, because it can be changed into a prime (202031211301) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 19801882 + ... + 19812081.

It is an arithmetic number, because the mean of its divisors is an integer number (8596230188).

Almost surely, 2202031211300 is an apocalyptic number.

202031211300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

202031211300 is an abundant number, since it is smaller than the sum of its proper divisors (416897362236).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

202031211300 is a wasteful number, since it uses less digits than its factorization.

202031211300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39613997 (or 39613990 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 202031211300 its reverse (3112130202), we get a palindrome (205143341502).

The spelling of 202031211300 in words is "two hundred two billion, thirty-one million, two hundred eleven thousand, three hundred".

Divisors: 1 2 3 4 5 6 10 12 15 17 20 25 30 34 50 51 60 68 75 85 100 102 150 170 204 255 300 340 425 510 850 1020 1275 1700 2550 5100 39613963 79227926 118841889 158455852 198069815 237683778 396139630 475367556 594209445 673437371 792279260 990349075 1188418890 1346874742 1980698150 2020312113 2376837780 2693749484 2971047225 3367186855 3961396300 4040624226 5942094450 6734373710 8081248452 10101560565 11884188900 13468747420 16835934275 20203121130 33671868550 40406242260 50507802825 67343737100 101015605650 202031211300