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20222311121300 = 22521931289812869
BaseRepresentation
bin1001001100100010111111…
…01010111100000110010100
32122121020022122001120211002
410212101133222330012110
510122310243121340200
6111002000153002432
74155004502253521
oct446213752740624
978536278046732
1020222311121300
116497263484962
1223272770b3418
13b38c56a47a22
144dca9d54a148
15251066de2bd5
hex12645fabc194

20222311121300 has 72 divisors (see below), whose sum is σ = 44144059625400. Its totient is φ = 8040760197120.

The previous prime is 20222311121281. The next prime is 20222311121303. The reversal of 20222311121300 is 312111322202.

It can be written as a sum of positive squares in 12 ways, for example, as 10048367447056 + 10173943674244 = 3169916^2 + 3189662^2 .

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20222311121303) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 24471266 + ... + 25284134.

Almost surely, 220222311121300 is an apocalyptic number.

20222311121300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20222311121300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22072029812700).

20222311121300 is an abundant number, since it is smaller than the sum of its proper divisors (23921748504100).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20222311121300 is a wasteful number, since it uses less digits than its factorization.

20222311121300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 814365 (or 814358 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 20222311121300 its reverse (312111322202), we get a palindrome (20534422443502).

The spelling of 20222311121300 in words is "twenty trillion, two hundred twenty-two billion, three hundred eleven million, one hundred twenty-one thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 193 386 772 965 1289 1930 2578 3860 4825 5156 6445 9650 12890 19300 25780 32225 64450 128900 248777 497554 812869 995108 1243885 1625738 2487770 3251476 4064345 4975540 6219425 8128690 12438850 16257380 20321725 24877700 40643450 81286900 156883717 313767434 627534868 784418585 1047788141 1568837170 2095576282 3137674340 3922092925 4191152564 5238940705 7844185850 10477881410 15688371700 20955762820 26194703525 52389407050 104778814100 202223111213 404446222426 808892444852 1011115556065 2022231112130 4044462224260 5055577780325 10111155560650 20222311121300