2111412130020 has 60 divisors (see below), whose sum is σ = 6623578057404. Its totient is φ = 563043234240.

The previous prime is 2111412130007. The next prime is 2111412130021. The reversal of 2111412130020 is 200312141112.

2111412130020 is a `hidden beast` number, since 211 + 14 + 121 + 300 + 20 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 629889846336 + 1481522283684 = 793656^2 + 1217178^2 .

It is a tau number, because it is divible by the number of its divisors (60).

It is a super-2 number, since 2×2111412130020² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 2111412129975 and 2111412130002.

It is not an unprimeable number, because it can be changed into a prime (2111412130021) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 651668791 + ... + 651672030.

Almost surely, 2^{2111412130020} is an apocalyptic number.

2111412130020 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

2111412130020 is an abundant number, since it is smaller than the sum of its proper divisors (4512165927384).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2111412130020 is a wasteful number, since it uses less digits than its factorization.

2111412130020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1303340842 (or 1303340831 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 2111412130020 its reverse (200312141112), we get a palindrome (2311724271132).

The spelling of 2111412130020 in words is "two trillion, one hundred eleven billion, four hundred twelve million, one hundred thirty thousand, twenty".