2111412141111 has 64 divisors (see below), whose sum is σ = 3767852325888. Its totient is φ = 1019869636608.

The previous prime is 2111412141001. The next prime is 2111412141161. The reversal of 2111412141111 is 1111412141112.

It is a happy number.

It is not a de Polignac number, because 2111412141111 - 2¹³ = 2111412132919 is a prime.

It is a super-2 number, since 2×2111412141111² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2111412141161) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 5976225 + ... + 6319658.

It is an arithmetic number, because the mean of its divisors is an integer number (58872692592).

Almost surely, 2^{2111412141111} is an apocalyptic number.

2111412141111 is a gapful number since it is divisible by the number (21) formed by its first and last digit.

2111412141111 is a deficient number, since it is larger than the sum of its proper divisors (1656440184777).

2111412141111 is a wasteful number, since it uses less digits than its factorization.

2111412141111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12295960.

The product of its digits is 64, while the sum is 21.

Adding to 2111412141111 its reverse (1111412141112), we get a palindrome (3222824282223).

Subtracting from 2111412141111 its reverse (1111412141112), we obtain a palindrome (999999999999).

The spelling of 2111412141111 in words is "two trillion, one hundred eleven billion, four hundred twelve million, one hundred forty-one thousand, one hundred eleven".