Base | Representation |
---|---|
bin | 11110110001000110110… |
… | …000100000101000000100 |
3 | 21111010101222012220112002 |
4 | 132301012300200220010 |
5 | 234120102111000200 |
6 | 4255145011044432 |
7 | 305516412144626 |
oct | 36610660405004 |
9 | 7433358186462 |
10 | 2114311031300 |
11 | 745746503586 |
12 | 2a19265a0718 |
13 | 1244bcc43870 |
14 | 7449442cc16 |
15 | 39ee87d7bd5 |
hex | 1ec46c20a04 |
2114311031300 has 72 divisors (see below), whose sum is σ = 4941279961800. Its totient is φ = 780621649920.
The previous prime is 2114311031293. The next prime is 2114311031351. The reversal of 2114311031300 is 31301134112.
It can be written as a sum of positive squares in 12 ways, for example, as 8422467076 + 2105888564224 = 91774^2 + 1451168^2 .
It is a super-2 number, since 2×21143110313002 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 27481286 + ... + 27558114.
Almost surely, 22114311031300 is an apocalyptic number.
2114311031300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2114311031300 is an abundant number, since it is smaller than the sum of its proper divisors (2826968930500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2114311031300 is a wasteful number, since it uses less digits than its factorization.
2114311031300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 98025 (or 98018 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 2114311031300 its reverse (31301134112), we get a palindrome (2145612165412).
The spelling of 2114311031300 in words is "two trillion, one hundred fourteen billion, three hundred eleven million, thirty-one thousand, three hundred".
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